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Quantities of materials for concrete such as cement, sand and aggregates for production of required quantity of concrete of given mix proportions such as 1:2:4 (M15), 1:1.5: 3 (M20), 1:1:2 (M25) can be calculated by absolute volume method.

This method is based on the principle that the volume of fully compacted concrete is equal to the absolute volume of all the materials of concrete, i.e. cement, sand, coarse aggregates and water.


A Concrete structure may consists of beams, slabs, columns and foundations etc. based on type of structure. The volume of concrete required for concrete structure can be calculated by summing up the volumes of each structural member or each parts of members.

The volume of a rectangular cross sectional member can be calculated as length x width x height (or depth or thickness). Suitable formula shall be used for different cross-sectional shapes of members.

The formula for calculation of materials for required volume of concrete is given by:


Where, Vc = Absolute volume of fully compacted fresh concrete

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W =Mass of water

C = Mass of cement

Fa = Mass of fine aggregates

Ca = Mass of coarse aggregates

Sc, Sfa and Sca are the specific gravities of cement, fine aggregates and coarse aggregates respectively.

The air content has been ignored in this calculation.

This method of calculation for quantities of materials for concrete takes into account the mix proportions from design mix or nominal mixes for structural strength and durability requirement.

Now we will learn the material calculation by an example.

Calculating Quantities of Materials for per cubic meter or cubic feet or cubic yards concrete

Consider concrete with mix proportion of 1:1.5:3 where, 1 is part of cement, 1.5 is part of fine aggregates and 3 is part of coarse aggregates of maximum size of 20mm. The water cement ratio required for mixing of concrete is taken as 0.45.

Assuming bulk densities of materials per cubic meter, cubic feet and cubic yards as follows:

Cement = 1500 kg/m3 = 93.642 lb/ft3 = 2528.332 lb/cubic yards

Sand = 1700 kg/m3 = 105 lb/ft3 = 2865.443 lb/cubic yards

Coarse aggregates = 1650 kg/m3 = 103 lb/ft3 = 2781.166 lb/cubic yards

Specific gravities of concrete materials are as follows:

Cement = 3.15

Sand = 2.6

Coarse aggregates = 2.6.

The percentage of entrained air assumed is 2%.

The mix proportion of 1:1.5:3 by dry volume of materials can be expressed in terms of masses as:

Cement = 1 x 1500 = 1500

Sand = 1.5 x 1700 = 2550

Coarse aggregate = 3 x 1650 = 4950.

Therefore, the ratio of masses of these materials w.r.t. cement will as follows =

Ratio of masses of cement, sand and coarse aggregates

= 1 : 1.7 : 3.3

The water cement ratio = 0.45

Now we will calculate the volume of concrete that can be produced with one bag of cement (i.e. 50 kg cement) for the mass proportions of concrete materials.

Thus, the absolute volume of concrete for 50 kg of cement =

Volume of concrete for 1 bag of cement

Thus, for the proportion of mix considered, with one bag of cement of 50 kg, 0.1345 m3 of concrete can be produced.

We have considered an entrained air of 2%. Thus the actual volume of concrete for 1 cubic meter of compacted concrete construction will be = 1 -0.02 = 0.98 m3.

Thus, the quantity of cement required for 1 cubic meter of concrete = 0.98/0.1345 = 7.29 bags of cement.

The quantities of materials for 1 m3 of concrete production can be calculated as follows:

The weight of cement required = 7.29 x 50 = 364.5 kg.

Weight of fine aggregate (sand) = 1.5 x 364.5 = 546.75 kg.

Weight of coarse aggregate = 3 x 364.5 = 1093.5 kg.

Concrete Calculator: Calculate Quantities of Materials for Concrete

Select Concrete Mix Proportion
Cement :
Sand :
Aggregates :
W/C Ratio :
Select Concrete Member*:
Dimension of Concrete Member
Length /Height: mm
Width : mm
Thickness / Depth : mm

Calculation Results: Quantities of Materials

Volume of Concrete = m3 = Yards = CFT = Pounds

Quantity of Cement = kg = Bags of 50 kg = Pounds

Quantity of Sand = kg = m3 = Yards = CFT = Pounds

Quantity of Coarse Aggregates = kg = m3 = Yards = CFT = Pounds

Quantity of Water = Liter = Gallons

Also Read:

Concrete Calculator – Calculate Concrete for Slab, Beam, Column and Footings

Concrete – Definition, Components, Manufacture, Construction and Articles

Reinforcement Calculator – Areas of Different Diameters and Numbers of Rebars

Rate Analysis of Brick Masonry -Calculate Quantity and Cost

Gopal Mishra

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  1. I want to know Following things:
    1. For 0.5 Cum Pan Mixer what will be Compacted Volume ?

    2. What all Aggregates Sizes Required with respect to their Size and Quantity?

    3. Amount of Water and Cement Max can be used?

    4. Amount of Sand ?

  2. I understood most of the article, but I am confused about the way you calculate weight of each materials that produce 1 m3 of concrete at the end of this article , where you use volumetric proportion instead of weight proportion

    Weight of fine aggregate (sand) = 1.5 x 364.5 = 546.75 kg. (I think it should be 1.7 instead of 1.5)

    Weight of coarse aggregate = 3 x 364.5 = 1093.5 kg. ( I think it should be 3.3 instead of 3 )

  3. But this is'nt actual formula …bcoz we r using grade M20 (1:1.5:3)..then cement is 8 bags/m3,sand 14.672 cft, nd coarse 29.672 cft..

  4. How much ( M15 – 1 2 4 ) wet concrete do we get with the above mix. Or what is the exact quantity of materials used in 1 cum ready mix concrete.

  5. I want to find how to determine the aggregate amount in concrete mix. Suppose-M25A20. Any one is having idea.

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