What will be Volume of Concrete for Given Cement Sand and Aggregate Quantity?

Volume of fully compacted concrete is given by following formula:

where V_c is the volume of concrete. W, C, F_a and C_a are the masses of water, cement, fine aggregates and coarse aggregates respectively.

Density of cement = 1500 kg/m³, fine aggregates = 1700 kg/m³ and coarse aggregates = 1650 kg/m³. 

So, Weight of cement C = 0.25 x 1500 = 375kg

Weight of Fine aggregates F_a = 0.25 x 1700 = 425 kg

Weight of Coarse aggregates C_a = 0.5 x 1650 = 825 kg

Consider w/c ratio as 0.45, so weight of water = 0.45×0.25×1000 = 112.5 L or kg

S_c, S_fa and S_ca are the specific weight of cement, fine aggregates and coarse aggregates which are 3.15 for cement and 2.6 for fine and coarse aggregates.

Therefore, putting these values in the formula above, we get

V_c = (112.5/1000)+(375/(1000×3.15))+(425/(1000×2.6))+(825/(1000×2.6)) = 0.712m³

So, Volume of concrete = 0.712m³