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How many cement bags and sand is required for M20 grade of concrete?

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Asked: July 31, 20202020-07-31T15:34:26-07:00 2020-07-31T15:34:26-07:00In: Concrete
Himanshu joshi
Himanshu joshi

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How many cement bags and sand is required for M20 grade of concrete?

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  1. RiyaJames

    RiyaJames

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    RiyaJames Beginner
    2020-09-19T14:33:30-07:00Added an answer on September 19, 2020 at 2:33 pm

    For an M20 grade of concrete, the ratio is (1:1.5:3) ie, (1 part of cement: 1.5 part of sand: 3 part of Aggregate)

    Let us assume for 1 Cum. Of M20 concrete,

    So, Wet volume of concrete = 1 Cum

    Dry volume of concrete = 1.54 times of the wet volume of concrete (Here 1.54 stands

    as “Factor of safety” to counter the shrinkage)

    = 1.54 Cum

    Total of ratio = 1 + 1.5 + 3 =5.5

    Therefore, Volume of Cement = (1/5.5) x 1.54 = 0.28 m3

    No. of Cement Bags = 0.28 x (1440 Kg/cum / 50 Kg/Cement Bag)

    = 0.28 x 28.8 = 8.064 Bags

    Say, 8 Bags of Cement

                       Volume of Sand        = (1.5/5.5) x 1.54 = 0.42 m3

    Say, 0.42 Cum of Sand

                   Volume of Aggregate   = (3/5.5) x 1.54 = 0.86 m3

    Say, 0.86 Cum of Aggregate

    NOTE: Density of Cement = 1440 Kg/Cum for one bag of  50 Kg cement

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  2. Vivek Patel

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    Vivek Patel User
    2020-07-31T23:14:30-07:00Added an answer on July 31, 2020 at 11:14 pm

    for 1 cubic meter, we calculate as follow

    let’s take dry mixture of aggregate sand and cement required is 1.52 cubic meter.

    M20 have an approximate proportion of cement sand and aggregate is 1:1.5:3

    cement in bag= (1/5.5.)x1.52/0.035 =7.89 say=8 bags

    sand in kg = (1.5/5.5)x1.52 x 1650 =684 kg

    aggregate in kg =(3/5.5) x 1.52 x 1700 =1410 kg

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  3. Jitendra45

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    Jitendra45 User
    2020-08-02T09:01:23-07:00Added an answer on August 2, 2020 at 9:01 am

    For calculating the quantity of cement, sand, aggregate, and water follow these steps:

    For one cubic meter of M20 (1:1.5:3)

    Wet volume of Concrete = 1 cum

    Dry volume of Concrete = 1.54 cum (increased by 54% for dry volume)

    Cement = 1.54/(1+1.5+3) × 28.8 = 8.064 say 8 bags. (1 cum = 28.8 bags)

    Sand = 1.54/(1+1.5+3) × 1.5 = 0.42 cum or 14.83 cft.

    Aggregate = 1.54/(1+1.5+3) × 3 = 0.84 cum or 29.66 cft.

    Water Quantity

    Assume water-cement ratio = 0.5

    Water required = water-cement ratio × Cement quantity (kg)

    = 0.5 × 400

    = 200 litres.

     

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  4. Komal Bhandakkar

    Komal Bhandakkar

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    Komal Bhandakkar AUTHOR
    2020-11-18T19:32:44-08:00Added an answer on November 18, 2020 at 7:32 pm

    Actually, the answer to your question is simple.

     

    • Since the bulk density of cement is 1440kg/cu.m. 
    • Mix proportion of M 20 grade of concrete = 1:1.5:3
    • Weight of one cement bag = 50kg.

    Required total dry volume of Material = 1.57 cu.m


    • Required Volume of cement = Ratio of cement x 1.57/(1+1.5+3)
    • Required Volume of cement = 1 x 1.57/5 .5
    • Required Volume of cement = 0.285 cu.m

    • Required Weight of cement = volume of cement x bulk density of cement
    • Required Weight of cement = 0.285 cu.m x 1440 kg/cu.m
    • Required Weight of cement = 410 kg

    • No of cement bags required = 410/50
    • No of cement bags required = 8.2 bags i.e. approximately 8 Nos.

    Hence, 8 bags of cement are required to prepare one cubic meter of M20 grade concrete.


    Thank You.

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  5. nikeetasharma

    nikeetasharma

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    nikeetasharma Guru
    2020-11-24T15:52:46-08:00Added an answer on November 24, 2020 at 3:52 pm

    Mostly the ratio of 1:1.5:3 is used for M20 grade of concrete

    So, Volume of dry concrete = 1.54 to 1.57 times volume of wet concrete

    Assume, 1cum of concrete work ratio sum = 1+1.5+3 = 5.5

    shrinkage or safety factor = 1.57

    Total volume of wet concrete required is = 1.57cum

    Volume of broken stone require = (3/5.5) * 1.57 = 0.856 m3

    Volume of sand require = (1.5/5.5) * 1.57 = 0.471 m3

    Volume of cement = (1/5.5) * 1.57 = 0.285 m3
    =0.285*1440 =411 kg

    For 1 m3 of M20 (1:1.5:3)

    Broken stone = 0.856 m3

    Sand = 0.472 m3

    Cement = 8.22 bag

    Therefore,
    8 bag of cement is required for 1cum of concrete work in M20

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